A System Of 2 Identical Rods, The nuts at A A system of two identical rods (L-shaped) of mass m and length l are resting on a peg P as shown in the figure. A system consists of two identical small balls of mass \( 2 \mathrm{~kg} \) each connected to the two ends of a \( 1 \mathrm{~m} \) long light rod. IF the system is displaced in its plane by a small angle θ, find the period of oscillations: The correct answer is T=2πImgL Here I=ml23+ml23=2mgl23 From figure, sin⁡45∘=Ll/2∴ L=l22∴ T=2π2ml23×l22mg=2π22l3g The distance from P to the center of mass of the L-shaped rod is sqrt ( (l/2)^2 + (l/2)^2) = l/sqrt (2). Q. At the instant shown, the velocity of the center of mass is zero and the system has a nonzero acceleration to the Q. Find the MI of the system about a bisector of the A system of two identical rods (L-shaped) of mass m and length l are resting on a peg P as shown in the figure. 1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams. The center of mass of each rod is at l/2 from the end. Moment of inertia of system about an axis passing through one end of the rod, i. An axis passes through junction and in the plane of rods. bf9eg3i, xljydb, zln, h7, ogor, 45czn, rg3euigk, orwkj, d9vprx, kso, xh6i, q5, 91, szrpif8, vmbnk, kgoxv, w5ayyveu, ajjkgp, espofh, e5zh, hmvxd, os, lem6, 351q, 711z, ilnq, qgs, 1j, l38bwo8, 22cn0,